1200000=t^2

Solution for 1200000=t^2 equation:

1200000=t^2

We move all terms to the left:

1200000-(t^2)=0

We add all the numbers together, and all the variables

-1t^2+1200000=0

a = -1; b = 0; c = +1200000;
Δ = b2-4ac
Δ = 02-4·(-1)·1200000
Δ = 4800000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4800000}=\sqrt{160000*30}=\sqrt{160000}*\sqrt{30}=400\sqrt{30}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-400\sqrt{30}}{2*-1}=\frac{0-400\sqrt{30}}{-2}
=-\frac{400\sqrt{30}}{-2}
=-\frac{200\sqrt{30}}{-1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+400\sqrt{30}}{2*-1}=\frac{0+400\sqrt{30}}{-2}
=\frac{400\sqrt{30}}{-2}
=\frac{200\sqrt{30}}{-1}
$